
so, we can convince ourselves that:
\cos \left( {2x} \right) = {\cos ^2}\left( x \right) – {\sin ^2}\left( x \right)
\sin \left( {2x} \right) = 2\sin \left( x \right)\cos \left( x \right)
so, we can convince ourselves that:
\cos \left( {2x} \right) = {\cos ^2}\left( x \right) – {\sin ^2}\left( x \right)
\sin \left( {2x} \right) = 2\sin \left( x \right)\cos \left( x \right)
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